Find all real numbers a that satisfy \frac{1}{64a^3 + 7} - 7 = 0.
164a3+7−7=0
Add 7 to both sides: 164a3+7=7
Multiply both sides by 64a^3 + 7 to get rid of denominator: 1=7(64a3+7); 1=448a3+49; −48=448a3; −328=a3
Cube rooting both sides, you get a=(−328)13, or noted as the cube root of -3/28.