Three gears of a transmission have a total of 85 teeth. While the first makes 5 revolutions, the second 9 and the third 15 times. How many teeth does each wheel have?
5+9+15 = 29 5 revs = 9 revs of 2nd 9 revs of 2nd = 15 revs of third
2nd gear has 5/9 as many teeth as 1st 3rd has 9/15 asmany as second = 9/15 * 5/9 as first
x + 5/9x + 9/15*5/9 x = 85
x = 45 then second has 25 and third has 15 teeth
5+9+15 = 29 5 revs = 9 revs of 2nd 9 revs of 2nd = 15 revs of third
2nd gear has 5/9 as many teeth as 1st 3rd has 9/15 asmany as second = 9/15 * 5/9 as first
x + 5/9x + 9/15*5/9 x = 85
x = 45 then second has 25 and third has 15 teeth