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Hey guys, I'm wondering if the following equation is a legit way of solving the following question. Here it comes:

 

A farmer harvested 5/8 of the field's crops and his son harvested 1/6 of the crops. The farmer harvests the remaindering crops by himself in 1 hour and 50 minutes. How long would it take for the farmer to harvest the entire field by himself?

 

X=Unknown/Answer

Z=Amount of crops farmed

 

X/4,8=(1-5/8+1/6)*Z=110

etc. etc.

X=5/24*Z*4,8=110*4,8

X=Z=528

X=528 Minutes

 

What I'm mainly concerned about is whether it's acceptable to have the Z there just as an indicator of what the fractions refer to, its value is hence always the same as the number it's multiplied with.

 Oct 21, 2016
edited by Guest  Oct 21, 2016
 #1
avatar+206 
+1

Wow, this is very complicated. Please help Melody <http://web2.0calc.com/members/Melody/> or CPhill <http://web2.0calc.com/members/CPhill/>.

 Oct 21, 2016
 #2
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A farmer harvested 5/8 of the field's crops and his son harvested 1/6 of the crops. The farmer harvests the remaindering crops by himself in 1 hour and 50 minutes. How long would it take for the farmer to harvest the entire field by himself?

 

5/8 + 1/6 =19/24 portion of harvest done by both men

1 - 19/24 =5/24 portion of harvest done by farmer himself in 1 hour and 50 minutes =1.8333 hours.

Therefore, the farmer could do the entire harvest by himself in:

24/5 x 1.83333=8.8 hours, or 8 hours and 48 minutes, or 528 minutes(which you got right.)

P.S. You Just need one variable X for the time rquired to harvest the entire field by himself.

 Oct 21, 2016
 #3
avatar+36919 
0

I think you are overthinking it:

 

Amount harvested by farmer and son = 5/8 + 1/6 = 19/24    so   5/24 left

 

110 minutes / ( 5/24 )   =  x min / (24/24) 

110 x 24/5  = 528 minutes to do it all alone.

 Oct 21, 2016
 #4
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Though a bit about it and I've made a new equation using you guys' advice.

 

X*(1-5/8+1/6)=110 Minutes 

Etc. etc

X*5/24=110

X=110*24/5

X=528

 Oct 22, 2016

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