ERMS is selling tickets to a musical performance. On the first day of ticket sales the school sold 8 adulttickets and 4 child tickets for 32 dollars. On the second day they sold 5 adult tickets and 3 child tickets for 21 dollars.
Find the price of an adult ticket and the price of a child ticket.
This is simply a system of equations and can be solved using substitution.
Let c represent the price of a child ticket.
Let a represent the price of an adult ticket.
We know:
5a +3c = 21
and
8a + 4c = 32
2a + c = 8
c = 8 - 2a
Now, using substitution:
5a +3c = 21
5a +3(8 - 2a) = 21
5a + 24 - 6a = 21
-a = -3
a = 3
c = 8 - 2a
c = 8 - 2(3)
c = 8 - 6
c = 2
Therefore the price of an adult ticket is $3 and the price of a child ticket is $2.