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avatar+191 

Hello, Everyone, do you think someone could help me to correct that ? 

 

A. Given g(x) = E^-2x+5 evamuate the following and round your answers to two decimal places  ( The exponant is the whole thing so -2x+5 

 

1. G(-1) I would said : e^-2*-1+5 so it would be E^7 ? Write ? 

 

2. G(3) I would said : E-2*3+5 = E^-1 ? 

 

3.G(2.5 ) e^-2*2.5+5 ? = E^0 ? 

 

I feel like Im doing it wrong witht he exponant calculation ? Right ? 

 

4. Graph rhe function F(x) = 2^x+1     so the exponant is x+1 

 

How I am supoosed to do that ??? there is no number given for x ?? Please help me I m so bad with maths even thought I tried my best to understand :( 

 

Best and thank you ! 

 

 

 
 Oct 29, 2015

Best Answer 

 #1
avatar+128407 
+10

You are exactly correct on your calculations of the exponents....good job!!!

 

You can evaluate the results you obtained with our on-site calculator......

 

4. Here's the graph  of 2^(x + 1).......https://www.desmos.com/calculator/qfcyl7dnde

 

It's just the graph of 2^x shifted to the left by one unit.....

 

 

cool cool cool

 Oct 29, 2015
edited by CPhill  Oct 29, 2015
 #1
avatar+128407 
+10
Best Answer

You are exactly correct on your calculations of the exponents....good job!!!

 

You can evaluate the results you obtained with our on-site calculator......

 

4. Here's the graph  of 2^(x + 1).......https://www.desmos.com/calculator/qfcyl7dnde

 

It's just the graph of 2^x shifted to the left by one unit.....

 

 

cool cool cool

CPhill Oct 29, 2015
edited by CPhill  Oct 29, 2015

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