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The loga5 = 2.935 and loga7 = 3.149, evaluate the expressions.

 

a. loga35

 

b. loga25/7

 

https://docs.google.com/document/d/1kyy9awHEPq_Q2eTYzUZcBgHnM4oypw59l-CRblp1V34/edit?usp=sharing

 

Tysm ~~~ 

 Dec 18, 2020
 #1
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Answers: 6.084 for (a), 2.721 for (b)

 

Generally, \(\log_a x\cdot y = \log_a x + \log_a y\). So log_a (5 * 7) = log_a (5) + log_a (7) = 2.935 + 3.149 = 6.084

 

Next, log_a (5*5) = log_a (5) + log_a (5) = 2.935 + 2.935 = 5.87. Then \(log_a {\frac{x}{y}} = log_a x - log_a y\). So log_a (25/7) = log_a (25) - log_a (7) = 5.87 - 3.149 = 2.721. Log rules are very important :)

 

You are very welcome!

:P

 Dec 18, 2020

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