i tried working it out but im not sure? can someone help explain ? thank you!
cos-1 (- √2/2) asks the question.....where does the cosine = -√2/2 ???
This is at 3pi/4
So sin (cos-1(-√2/2)) = sin (3pi/4) = √2/2
And notice that sin (pi/2) = 1
So tan-1 (1) asks the question......where does the tan = 1 ???
This is at pi/4
So....puuting this altogether we have
√2/2 + pi/4 =
2√2 + pi