We have ab=cd
Prove that (a−3×b)(5×b)=(c−3×d)(5×c)
: (a-3 b)/(5 b) = (c-3 d)/(5 c) true OR false?
IT'S FALSE!!!!.
If a/b = c/d
then subtract 3 from both sides:
---> a/b - 3 = c/d - 3
which becomes: a/b - 3b/b = c/d - 3d/d
---> (a - 3b)/b = (c - 3d)/d
Multiply both sides by 1/5:
---> (a - 3b)/(5b) = (c - 3d)/(5d)
Did you mistype the problem?
If a/b=c/d then prove that
(a-3b)/(5.b) = (c-3*d)/(5c)
A very simple proof:let a=1, b=2, c=3, d=6 so that we have 1/2=3/6.Now substitute as follows: (1 - 3*2)/(5*2)=(3- 3*6)/(5*3)
We have(-5)/10=-15/15
Therfore -1/5 =-1 !!!!!!!!!!!!!!!!!!!!!!!! Where did get this gem from?
SORRY!! I meant: -1/2=-1 instead of -1/5=-1