Here's the expression: \(({2x -5 \over 5 -x })({5-x \over 5 -x })\)

Did I solve this right? Here's what I did:

\({ 10x - 2x^2 - 25 + 5x \over 25 - 5x -5x + x^2}\)

\({-2x^2 + 15x -25\over x^2 -10x +25}\) (this is my answer)

Guest Mar 31, 2018

#1**+3 **

You're right that \((\frac{2x-5}{5-x})(\frac{5-x}{5-x})\) *is* equivalent to \(\frac{-2x^2+15x-25}{x^2-10x+25}\)

....What do the full directions say?

hectictar
Mar 31, 2018