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 expanding this rational expression?

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Here's the expression: \(({2x -5 \over 5 -x })({5-x \over 5 -x })\)

Did I solve this right? Here's what I did:

\({ 10x - 2x^2 - 25 + 5x \over 25 - 5x -5x + x^2}\)

\({-2x^2 + 15x -25\over x^2 -10x +25}\) (this is my answer)

 Mar 31, 2018

4+0 Answers

 #1
avatar+9466 
+3

You're right that   \((\frac{2x-5}{5-x})(\frac{5-x}{5-x})\)  is equivalent to  \(\frac{-2x^2+15x-25}{x^2-10x+25}\)

 

....What do the full directions say?

 Mar 31, 2018
 #3
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+1

"Create three sample expressions written in the form \({ax^2 + bx + c \over dx^2 + ex + f}\) where the numerators and denominators factor and the expressions can be simplified." That was just one of them, and I wanted to make sure if my answer was right :)

Guest Apr 1, 2018
 #4
avatar+9466 
+3

Ah thank you for the response! I didn't know whether it wanted the expression in simplest form.....but since it doesn't, your answer is correct!  smiley

hectictar  Apr 1, 2018
 #2
avatar+118609 
+2

\(({2x -5 \over 5 -x })({5-x \over 5 -x })={2x -5 \over 5 -x }\)

.
 Mar 31, 2018

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