Suppose we have a bag with 10 slips of paper in it. Eight slips have a 3 on them and the other two have a 9 on them. What is the expected value of the number shown when we draw a single slip of paper?
I know this was already similarly answered, however, I do not know the formula for this.
Thank you
Take each value times it's probability and sum them
3 * 1/10 + 3 * 1/10 ......+ 9* 1/10 + 9 * 1/10 =
7 * 3 * 1/10 + 2 * 9 * 1/10
21/10 + 18/10
= 3.9 ( in this case it is just the average of all of the slips)
+36915 It IS wrong....and if you read through the solution YOU should have seen why...there is EIGHT 3's, not seven.....kinda proves you are just looking for answers and not understanding/learning...don't be that guy/girl....
Take each value times it's probability and sum them
3 * 1/10 + 3 * 1/10 ......+ 9* 1/10 + 9 * 1/10 =
8 * 3 * 1/10 + 2 * 9 * 1/10
24/10 + 18/10
= 4.2 ( in this case it is just the average of all of the slips)
