I need help with these
Suppose we have a bag with 10 slips of paper in it. Eight slips have a 3 on them and the other two have a 5 on them.
(a) What is the expected value of the number shown when we draw a single slip of paper?
(b) What is the expected value of the number shown if we add one additional 3 to the bag?
(c) What is the expected value of the number shown if we add two additional 3's (instead of just one) to the bag?
+44 (a): there is a 8/10 probability of pulling a 3 and a 2/10 probability of pulling a 5 so the expected value is \(\frac{8}{10}(3) + \frac{2}{10}(5)\) Expected value for drawing one slip of paper, this is equal to 3.4 or 34/10 or 17/5
(b): well, this would be the exact same idea except the probabilities are different, now the expected value is \(\frac{9}{11}(3) + \frac{2}{11}(5)\) which simplifies to 37/11
(c): Once again, same idea, the expected value would be \(\frac{10}{12}(3) + \frac{2}{12}(5)\) which simplifies to 10/3
If you have any questions, just ask :)
