+0  
 
0
629
2
avatar+605 

Explain how to solve 5x 2 - 3x = 25 by completing the square. What are the solutions?

 Jan 28, 2019
 #1
avatar+140 
+1

1. Put all terms with variable on one side and the constants on the other side.5x^2 - 3x = 252.

Factor out the coefficient of the x^2 term

.5(x^2 - 3x/5) = 253.

Inside the parentheses, we add a number that would complete the square and also add this to the other side of the equation.

In this case we add 9/100 and on the other  side we add 9/20.5(x^2 - 3x/5 + 9/100) = 25 + 9/204.

We simplify as follows:

5(x^2 - 3x/5 + 9/100) = 25 + 9/205(x - 3/10)^2 = 509/20(x - 3/10)^2 = 509/100x1 = √(509) /100 + 3/10x2  = -√(509) /100 + 3/10

 Jan 28, 2019
 #2
avatar+106532 
+1

Thanks, Mclovin.....here's another way...

 

5x ^2 - 3x = 25     divide through by 5

 

x^2  - (3/5)x  =  5         

 

Take (1/2) of (3/5) = 3/10....square it = 9/100.....add to both sides

 

x^2 - (3/5)x + 9/100 =  5 + 9/100      factor the right side

 

(x - 3/10)^2 =   509/100    take both roots

 

x - 3/10 =  ±√ [509/100]

 

x - 3/10 = ±√(509) /10     add 3/10 to both sides

 

x =     [ 3 ±√509 ] / 10

 

 

cool cool cool

 Jan 28, 2019

12 Online Users

avatar