+22 A colony of bacteria is grown so that the population increases exponential with time. At the end of 3 hours there are 10,000 bacteria. At the end of 5 hours there are 40,000 bacteria. How many bacteria were present intially?
+5265 This is a geometric sequence, where the function is 2n, n being the number of bacteria.
Divide 40,000 by 2. 5th hour.
20,000 is the answer, divide 20,000 by 2. 4th hour.
10,000 is the answer, divide 10,000 by 2. 3rd hour.
5,000 is the answer. Divide 5000 by 2 2nd hour.
2,500 is the answer. Divide by 2 to find the initial amount. 1st hour.
The initial amount is 1,250 bacteria.
Hope this helped! :D
+5265 This is a geometric sequence, where the function is 2n, n being the number of bacteria.
Divide 40,000 by 2. 5th hour.
20,000 is the answer, divide 20,000 by 2. 4th hour.
10,000 is the answer, divide 10,000 by 2. 3rd hour.
5,000 is the answer. Divide 5000 by 2 2nd hour.
2,500 is the answer. Divide by 2 to find the initial amount. 1st hour.
The initial amount is 1,250 bacteria.
Hope this helped! :D
A colony of bacteria is grown so that the population increases exponential with time. At the end of 3 hours there are 10,000 bacteria. At the end of 5 hours there are 40,000 bacteria. How many bacteria were present intially
40,000 /10,000=4x increase in bacterial count in 5-3=2 hours, therefore the exponential rate of inrease is=sqrt(4)=2 - 1 =1 X 100=100%.
Since the population doubles every hour, we therefore have in 3 hours:
10,000 / (2^3) =1,250 The initial population of bacterial colony.
