Exponents

(3^2)^y = 3^5  *  (3^2)^6   *  (3^4)^4  / (3^3)^3

3^2y     =  3^5+12+16 / 3⁹

3^{2y     =}  3³³ /3⁹  

3^2y   =  3²⁴            now equate the exponents and solve for y

2y  = 24

y = 12                 (IF I made no errors......check my work ! )

Converting everything to 3. 

3^(2y) = 3^(5) * 3^(12) * 3^(16) * 3^(-9)

3^(2y) = 3^(24)

2y = 24

y = 12

Yayyyy, EP and I got the same answer. :))

=^._.^=