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Find the value of y such that 9^y = 3^5 * 9^6 * 81^4/27^3.

 May 28, 2021
 #1
avatar+34340 
+2

(3^2)^y = 3^5  *  (3^2)^6   *  (3^4)^4  / (3^3)^3

 

32y     =  35+12+16 / 39

 

32y     =  333 /39  

32y   =  324            now equate the exponents and solve for y

 

2y  = 24

y = 12                 (IF I made no errors......check my work ! )

 May 28, 2021
 #2
avatar+2205 
+1

Converting everything to 3. 

3^(2y) = 3^(5) * 3^(12) * 3^(16) * 3^(-9)

3^(2y) = 3^(24)

2y = 24

y = 12

 

Yayyyy, EP and I got the same answer. :))

 

=^._.^=

 May 28, 2021
 #3
avatar+34340 
+1

DOUBLE  Yayy!  catmg   and  I   got the same result ! !   cheeky    ( or we made the same mistakes....LOL)

ElectricPavlov  May 28, 2021
edited by ElectricPavlov  May 28, 2021

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