3^5/27^3
3^5 / ( 3^3)^3
3^5 / 3^9
3^-4 for the right side
for the left side
(3^2)^y
so 3^(2y) = 3^(-4) can you finish from here (Hint: equate the exponents)
+678 Hi Guest,
\(9^y=\frac{3^5}{27^3}\)
\(\mbox {Calculate}\)
\(9^y=\frac{243}{19683}\)
\(\mbox {Now divide with 243}\)
\(9^y=\frac{1}{81}\)
\(\mbox {Write the expression in exponential form with the base of 3}\)
\({3}^{2y}=\frac{1}{81}\)
\(\mbox {Write the expression in exponential form with the base of 3}\)
\({3}^{2y}={3}^{-4}\)
\(\mbox {Since the bases are the same, set the exponents equal}\)
\(2y=-4\)
\(\mbox {Divide both sides of the equation by 2}\)
\(y=-2\)
Here's your answer.
!
