Exponents

3^5/27^3

3^5  / ( 3^3)^3

3^5 / 3^9

3^-4   for the right side

for the left side

(3^2)^y 

so    3^(2y) = 3^(-4)      can you finish from here (Hint: equate the exponents)

Hi Guest,

$9^y=\frac{3^5}{27^3}$

$\mbox {Calculate}$

$9^y=\frac{243}{19683}$

$\mbox {Now divide with 243}$

$9^y=\frac{1}{81}$

$\mbox {Write the expression in exponential form with the base of 3}$

${3}^{2y}=\frac{1}{81}$

$\mbox {Write the expression in exponential form with the base of 3}$

${3}^{2y}={3}^{-4}$

$\mbox {Since the bases are the same, set the exponents equal}$

$2y=-4$

$\mbox {Divide both sides of the equation by 2}$

$y=-2$

Here's your answer.

 !