+2668 We can write this as an equation: \({1 \over 9}^3 = 9^n \times 27^n\)
We can rewrite these in powers of 3 as: \(3^{-6} =3^{2n} \times 3^{3n}\)
Because the bases are the same, we can rewrite this as an equation with n: \(-6 = 5n\)
Simplifying, we find \(\color{brown}\boxed{n=-1.2}\)
+130071 (1/9)^3 = 27 * 9^n
9^(-3) = 3^3 * 9^n
(3^2)^(-3) = 3^3 * ( 3^2)^n
3^ (-6) = 3^3 * 3^(2n)
3 ^ (-6) = 3^ ( 3 + 2n)
Solve for the exponents
-6 = 3 + 2n
-6 - 3 = 2n
-9 = 2n
n = -9/2
+2668 We can write this as an equation: \({1 \over 9}^3 = 9^n \times 27^n\)
We can rewrite these in powers of 3 as: \(3^{-6} =3^{2n} \times 3^{3n}\)
Because the bases are the same, we can rewrite this as an equation with n: \(-6 = 5n\)
Simplifying, we find \(\color{brown}\boxed{n=-1.2}\)
