To express (3x-40) (6x+4) as a trinomial, multiply the two binomials.
(3x-40)
* (6x+4) -Just multiply like you usually would if they were numbers
----------------
12x -160
+ 18x2 -240x + 0 -add them up
-----------------
18x2 - 228x - 160
So (18x2 - 228x - 160) is your trinomial
To check it, put in a number for x on both equations.
(3(5)-40)*(6(5)+4) =
(15 - 40)*(30+4) =
(-25)*(34)
= -850
(18(5)2 - 228(5) - 160)=
(450-1140 - 160)
= -850 ✔
To express (3x-40) (6x+4) as a trinomial, multiply the two binomials.
(3x-40)
* (6x+4) -Just multiply like you usually would if they were numbers
----------------
12x -160
+ 18x2 -240x + 0 -add them up
-----------------
18x2 - 228x - 160
So (18x2 - 228x - 160) is your trinomial
To check it, put in a number for x on both equations.
(3(5)-40)*(6(5)+4) =
(15 - 40)*(30+4) =
(-25)*(34)
= -850
(18(5)2 - 228(5) - 160)=
(450-1140 - 160)
= -850 ✔
I wish people would be more careful when they enter their questions.
Members can edit theirs but non-memebers need to take exceptional care!
I susupect it was suppose to be 4 and the zero was meant to be a bracket but not to worry the technique is very similar.
I think you have done it back to front from what is usual. But the answer (to the question that you answsered) is still correct.