+0

# express (3x-40 (6x+4)

0
518
2

express (3x-40 (6x+4) as a trinomial

Jun 5, 2014

#1
+5

To express (3x-40) (6x+4) as a trinomial, multiply the two binomials.

(3x-40)

* (6x+4)       -Just multiply like you usually would if they were numbers

----------------

12x -160

+ 18x2 -240x + 0      -add them up

-----------------

18x2 - 228x - 160

So (18x2 - 228x - 160) is your trinomial

To check it, put in a number for x on both equations.

(3(5)-40)*(6(5)+4) =

(15 - 40)*(30+4) =

(-25)*(34)

= -850

(18(5)2 - 228(5) - 160)=

(450-1140 - 160)

= -850 ✔

Jun 5, 2014

#1
+5

To express (3x-40) (6x+4) as a trinomial, multiply the two binomials.

(3x-40)

* (6x+4)       -Just multiply like you usually would if they were numbers

----------------

12x -160

+ 18x2 -240x + 0      -add them up

-----------------

18x2 - 228x - 160

So (18x2 - 228x - 160) is your trinomial

To check it, put in a number for x on both equations.

(3(5)-40)*(6(5)+4) =

(15 - 40)*(30+4) =

(-25)*(34)

= -850

(18(5)2 - 228(5) - 160)=

(450-1140 - 160)

= -850 ✔