#1**+5 **

To express (3x-40) (6x+4) as a trinomial, multiply the two binomials.

(3x-40)

* (6x+4) -Just multiply like you usually would if they were numbers

----------------

12x -160

+ 18x^{2} -240x + 0 -add them up

-----------------

18x^{2} - 228x - 160

So (18x^{2} - 228x - 160) is your trinomial

To check it, put in a number for x on both equations.

(3(5)-40)*(6(5)+4) =

(15 - 40)*(30+4) =

(-25)*(34)

= -850

(18(5)^{2} - 228(5) - 160)=

(450-1140 - 160)

= -850 ✔

NinjaDevo Jun 5, 2014

#1**+5 **

Best Answer

To express (3x-40) (6x+4) as a trinomial, multiply the two binomials.

(3x-40)

* (6x+4) -Just multiply like you usually would if they were numbers

----------------

12x -160

+ 18x^{2} -240x + 0 -add them up

-----------------

18x^{2} - 228x - 160

So (18x^{2} - 228x - 160) is your trinomial

To check it, put in a number for x on both equations.

(3(5)-40)*(6(5)+4) =

(15 - 40)*(30+4) =

(-25)*(34)

= -850

(18(5)^{2} - 228(5) - 160)=

(450-1140 - 160)

= -850 ✔

NinjaDevo Jun 5, 2014

#2**0 **

I wish people would be more careful when they enter their questions.

Members can edit theirs but non-memebers need to take exceptional care!

I susupect it was suppose to be 4 and the zero was meant to be a bracket but not to worry the technique is very similar.

I think you have done it back to front from what is usual. But the answer (to the question that you answsered) is still correct.

Melody Jun 6, 2014