We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
+1
77
1
avatar

\(12^2 = 144\)

 

So I learned that the basic log function is the inverse of exponential y = c\({^x}\)

Therefore...

y = c\({^x}\)

x = c\({^y}\)

log\({_c}\)x = log\({_c}\)c\({^y}\) (the log & c cancel...)

log\({_c}\)x = y

 

When I applied this to \(12^2 = 144\) I got log\({_{12}}\)2 = 144 while the answer in the textbook is log\({_{12}}\)144 = 2.

 

What did I do wrong?

 Apr 23, 2019
 #1
avatar+667 
+2

\(b^x=y\) is the exponential form.

 

\(log_by=x\) is the log form.

 

The exponential form is \(12^2=144\).

 

You likely switched the X and Y when you wrote the log formula.

 

So since the y is 144,

 

you were supposed to have \(log_{12}\boxed{144}=2\)

 

The 144 is the part you messed up, as you switched the x and y.

 Apr 23, 2019

11 Online Users