A square pyramid has a height h and a base with side length b. The side lengths of the base increase by 50%. Write a simplified expression that represents the volume of the new pyramid in terms of b and h.
+592 Volume of the pyramid = \(\frac{1}{3} \cdot b^2h\)
If the sides increased by 50%, the new volume would be:
\(\frac{1}{3} \cdot (1.5b)^2h = \frac{1}{3} \cdot 2.25b^2h = \frac{3}{4}\cdot b^2h\)
