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# f(θ) = −1.75 cos(1/2(θ + 60°)) ; θ is in degrees.

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f(θ) = −1.75 cos(1/2(θ + 60°)) ; θ is in degrees.

period and amplitude?

Dec 3, 2015

#2
+109512
+10

This is a post that I did on  this topic  a year and a half ago :)

http://web2.0calc.com/questions/graphing-trig-functions_1#rr2

and here is another by Alan

http://web2.0calc.com/questions/can-anyone-remember-the-formulas-of-period-phase-shift-and-range-of-the-sin-function#r5

Dec 3, 2015

#1
+111321
+10

f(θ) = −1.75 cos(1/2(θ + 60°))   we can simplify this as

f(θ) = −1.75 cos([θ/2 + 30°]

The period is given by

θ/2   = 360°

θ = 720°

The amplitude is  =  abs [ -1.75]   = 1.75

Here's the graph :  https://www.desmos.com/calculator/7mhnsqww6c

Dec 3, 2015
#2
+109512
+10

This is a post that I did on  this topic  a year and a half ago :)

http://web2.0calc.com/questions/graphing-trig-functions_1#rr2

and here is another by Alan

http://web2.0calc.com/questions/can-anyone-remember-the-formulas-of-period-phase-shift-and-range-of-the-sin-function#r5

Melody Dec 3, 2015
#3
+111321
+5

Thanks, Melody, for that reference......

Dec 3, 2015