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f(θ) = −1.75 cos(1/2(θ + 60°)) ; θ is in degrees.

 

period and amplitude?

 Dec 3, 2015

Best Answer 

 #2
avatar+109512 
+10

This is a post that I did on  this topic  a year and a half ago :)

 

http://web2.0calc.com/questions/graphing-trig-functions_1#rr2

 

and here is another by Alan

 

http://web2.0calc.com/questions/can-anyone-remember-the-formulas-of-period-phase-shift-and-range-of-the-sin-function#r5

 Dec 3, 2015
 #1
avatar+111321 
+10

f(θ) = −1.75 cos(1/2(θ + 60°))   we can simplify this as

 

f(θ) = −1.75 cos([θ/2 + 30°]

 

The period is given by

 

θ/2   = 360°

 

θ = 720°

 

The amplitude is  =  abs [ -1.75]   = 1.75

 

Here's the graph :  https://www.desmos.com/calculator/7mhnsqww6c

 

 

cool cool cool

 Dec 3, 2015
 #2
avatar+109512 
+10
Best Answer

This is a post that I did on  this topic  a year and a half ago :)

 

http://web2.0calc.com/questions/graphing-trig-functions_1#rr2

 

and here is another by Alan

 

http://web2.0calc.com/questions/can-anyone-remember-the-formulas-of-period-phase-shift-and-range-of-the-sin-function#r5

Melody Dec 3, 2015
 #3
avatar+111321 
+5

Thanks, Melody, for that reference......

 

 

 

cool cool cool

 Dec 3, 2015

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