$f(x)$ is a monic polynomial such that $f(0)=4$ and $f(1)=10$. If $f(x)$ has degree $2$, what is $f(x)$? Express your answer in the form $ax^2+bx+c$, where $a$, $b$, and $c$ are real numbers.
A monic polynomial is a polynomial where the cofficient of the highest order term is 1. (I didn't know this until now, I had to look it up here.)
f(x) is a monic polynomial with a degree of 2. So we can say...
f(x) = 1x2 + bx + c = x2 + bx + c
The problem says f(0) = 4 . So...
f(0) = 02 + b(0) + c
4 = 0 + 0 + c
4 = c
Now that we know c = 4 , we know that f(x) = x2 + bx + 4 .
The problem says f(1) = 10 . So...
f(1) = 12 + b(1) + 4
10 = 1 + b + 4
10 = 5 + b
5 = b
Now we know b = 5 and c = 4 , so f(x) = x2 + 5x + 4 .
A monic polynomial is a polynomial where the cofficient of the highest order term is 1. (I didn't know this until now, I had to look it up here.)
f(x) is a monic polynomial with a degree of 2. So we can say...
f(x) = 1x2 + bx + c = x2 + bx + c
The problem says f(0) = 4 . So...
f(0) = 02 + b(0) + c
4 = 0 + 0 + c
4 = c
Now that we know c = 4 , we know that f(x) = x2 + bx + 4 .
The problem says f(1) = 10 . So...
f(1) = 12 + b(1) + 4
10 = 1 + b + 4
10 = 5 + b
5 = b
Now we know b = 5 and c = 4 , so f(x) = x2 + 5x + 4 .