Consider the function f(x)=(x²-1)/(x²+3x+2)
a) Identify any asymptotes and/or holes. If there are any vertical asymptotes, state the behaviour of the graph on both sides.
b) State the domain and range.
c) Graph f(x).
f(x)=(x²-1)/(x²+3x+2)
\(f(x)=\frac{(x²-1)}{(x²+3x+2)}\\ f(x)=\frac{(x-1)(x+1)}{(x+2)(x+1)}\\ \text{there is a hole at x=1 because you cannot divide by 0}\\ f(x)=\frac{(x-1)}{(x+2)}\\ \text{There is an asymptote at x=-2} \)
You can finish it :)
+180 
