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avatar+44 

Factor completely

 

2x^2+7x+6

 

A. (2x-3)(x-2)

B. (2x+3)(x+3)

C.Prime

D. (x+3)(2x+2)

 Dec 16, 2020
 #1
avatar+117546 
+1

Let's see...we need  two integers that  multiply to 2   =  1, 2

And  2 two integers that multiply to 6  =  1, 6  or  3,2

Every term is positive...so no negatives  will apply

 

So....let's try

 

(2x + 3) ( x + 2)       hey ....got  it  on the  first try  !!!

 

Proof

2x*x + 2x*2  + 3*x  + 3*2  =

2x^2 + 4x + 3x + 6  =

2x^2  + 7x + 6  =     just what we started with  !!!

 

 

cool cool cool

 Dec 16, 2020
edited by CPhill  Dec 16, 2020
 #2
avatar+2 
+1

if you want write a super script or small text formula - www.abtextgenerator.com/small-text

 Dec 17, 2020

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