+0

# Factor problem, need halp

0
58
3
+153

Factor the following:
\[ -8x^2y^4z^3 + 12x^4yz^3.\]

Nov 18, 2020

### 3+0 Answers

#1
+114221
+2

-8x^2y^4z^3  + 12x^4 yz^3    =

-4x^2 y z^3    ( 2y^3 - 3x^2)

Do you see how I did that, T4H???

Nov 18, 2020
#2
+114221
+2

OK

Take out the lowest common factor beteen  - 8  and  12.....to make matters simple....I'll use 4 in this example

Take out  the lowest common factoe  between x^2 and x^4  = x^2

Take our the lowest common factor  between y^4 and y  =  y

Take out the lowest common factor between z^3 and z^3  = z^3

On the outside of the parentheses we will just write  these in order   =    4x^2yz^3

To find out what goes in the parentheses  we just  fivide each  term in the original problem by 4x^2y z^3

So   -8x^2y^4z^3                            And    12x^4yz^3

___________  =   -2y^3                      ________    =    3x^2

4x^2yz^3                                            4x^2 y z^3

Putting this all together  we get

4x^2yz^3  ( -2y^3 + 3x^2)

Nov 18, 2020
#3
+153
+1

Oh ok

Thanks4helping  Nov 18, 2020