+8581 12 • (2x + y2)^2
((48•(x2))+(48x•(y2)))+(22•3y4)
Pull out like factors :
48x2 + 48xy2 + 12y4 = 12 • (4x2 + 4xy2 + y4)
4x2 + 4xy2 + y4
: (2x + y2)•(2x + y2)
4x2 +4xy2 +y4
12 • (2x + y2)2
:D :D
Factor the following: 48 x^2+48 x y^2+12 y^4 Factor 12 out of 48 x^2+48 x y^2+12 y^4: 12 (4 x^2+4 x y^2+y^4) 4 x^2+4 x y^2+y^4 = 4 x^2+4 x y^2+1 (y^2)^2: 12 4 x^2+4 x y^2+(y^2)^2 The factors of 4 that sum to 4 are 2 and 2. So, 4 x^2+4 x y^2+(y^2)^2 = (y^2+2 x) (y^2+2 x): 12 (y^2+2 x) (y^2+2 x) (y^2+2 x) (y^2+2 x) = (y^2+2 x)^2: Answer: | | 12 (y^2+2x)^2
