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# Factoring an equation

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how do i factor out 6x^2-x-1?

Guest Oct 29, 2015

#1
+1792
+10

Since the constant term is -1 you know your factors are going to be

\(6x^2 -x -1 = (a x + 1)(b x -1) = (ab)x^2+(b-a)x-1\)

\(a b =6, (b-a)=-1 \\ b=a-1 \\ a(a-1) = 6 \\ a=3, b=2\)

\(6x^2-x-1 = (3x+1)(2x-1)\)

Rom  Oct 29, 2015
Sort:

#1
+1792
+10

Since the constant term is -1 you know your factors are going to be

\(6x^2 -x -1 = (a x + 1)(b x -1) = (ab)x^2+(b-a)x-1\)

\(a b =6, (b-a)=-1 \\ b=a-1 \\ a(a-1) = 6 \\ a=3, b=2\)

\(6x^2-x-1 = (3x+1)(2x-1)\)

Rom  Oct 29, 2015
#2
+91784
0

Thansk Rom

I would not have done it like that but I like that logic.

To use Chris's expression,  "I will put that in my tool belt"

I think that is what chris says anyway LOL

Melody  Oct 29, 2015

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