how do i factor out 6x^2-x-1?

Since the constant term is -1 you know your factors are going to be

\(6x^2 -x -1 = (a x + 1)(b x -1) = (ab)x^2+(b-a)x-1\)

\(a b =6, (b-a)=-1 \\ b=a-1 \\ a(a-1) = 6 \\ a=3, b=2\)

\(6x^2-x-1 = (3x+1)(2x-1)\)

Thansk Rom

I would not have done it like that but I like that logic.

To use Chris's expression, "I will put that in my tool belt"

I think that is what chris says anyway LOL