+0  
 
+5
85
7
avatar+251 

Assuming that x is not 3, simplify: \(\dfrac{8x-4}{x+3} - \dfrac{12x-20}{2x+6}\)

 

So far I was able to factor the second term: \(\frac{12x-20}{2x+6}=\frac{4(3x-5)}{2(x+3)}=2(3x-5).\)

 

I plugged 2(3x-5) back into the expression, but I don't know what to do from here. Could I get a hint?

 Feb 10, 2022
 #1
avatar+125 
-3

srry i dont know how to do that what grade are you even in

 Feb 10, 2022
 #4
avatar+251 
+1

7th grade

dolphinia  Feb 10, 2022
 #7
avatar+1351 
+1

Me too lol...

BuilderBoi  Feb 19, 2022
 #2
avatar+36416 
+1

Divide the second term by 2/2   to get

 [(8x-4)    -   (6x-10) ]   /   ( x+3)   = 

 

(2x +6)  / (x+3)

2 (x+3) / (x+3)   = 2

 Feb 10, 2022
 #5
avatar+251 
+1

so the answer is 2??

dolphinia  Feb 10, 2022
 #3
avatar+36416 
0

....and here is an error      4(3x-5)/2(x+3)   =  2 (3x-5) / (x+3)       ( you dropped the denominator by accident)  

 Feb 10, 2022
 #6
avatar+251 
+4

Ohh haha I see that now... thanks for correcting me!

dolphinia  Feb 12, 2022

27 Online Users