+0

# Factoring Expression

+5
145
7
+251

Assuming that x is not 3, simplify: $$\dfrac{8x-4}{x+3} - \dfrac{12x-20}{2x+6}$$

So far I was able to factor the second term: $$\frac{12x-20}{2x+6}=\frac{4(3x-5)}{2(x+3)}=2(3x-5).$$

I plugged 2(3x-5) back into the expression, but I don't know what to do from here. Could I get a hint?

Feb 10, 2022

#1
+114
-3

srry i dont know how to do that what grade are you even in

Feb 10, 2022
#4
+251
+1

dolphinia  Feb 10, 2022
#7
+2437
0

Me too lol...

BuilderBoi  Feb 19, 2022
#2
+36433
+1

Divide the second term by 2/2   to get

[(8x-4)    -   (6x-10) ]   /   ( x+3)   =

(2x +6)  / (x+3)

2 (x+3) / (x+3)   = 2

Feb 10, 2022
#5
+251
+1

dolphinia  Feb 10, 2022
#3
+36433
0

....and here is an error      4(3x-5)/2(x+3)   =  2 (3x-5) / (x+3)       ( you dropped the denominator by accident)

Feb 10, 2022
#6
+251
+4

Ohh haha I see that now... thanks for correcting me!

dolphinia  Feb 12, 2022