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show steps of how to sovle for two terms

x^3+9769

gadzooks1753  Nov 28, 2017

Best Answer 

 #1
avatar+2255 
+1

In this case, we are utilizing the rule of a sum of cubes. The rule is the following:

 

\(a^3+b^3=(a+b)(a^2-ab+b^2)\)

 

To remember the signs, you can remember this acronym. "soap." The acronym dictates the signage sequentially. 

 

Same sign

Opposite sign

Always

Positive

 

\(a=x\\ b=\sqrt[3]{9769}\)

 

9769 is not a perfect cube, so this is the best we can do.

 

\((x+\sqrt[3]{9769})(x^2-x\sqrt[3]{9769}+\sqrt[3]{9769}^2)\)

TheXSquaredFactor  Nov 28, 2017
 #1
avatar+2255 
+1
Best Answer

In this case, we are utilizing the rule of a sum of cubes. The rule is the following:

 

\(a^3+b^3=(a+b)(a^2-ab+b^2)\)

 

To remember the signs, you can remember this acronym. "soap." The acronym dictates the signage sequentially. 

 

Same sign

Opposite sign

Always

Positive

 

\(a=x\\ b=\sqrt[3]{9769}\)

 

9769 is not a perfect cube, so this is the best we can do.

 

\((x+\sqrt[3]{9769})(x^2-x\sqrt[3]{9769}+\sqrt[3]{9769}^2)\)

TheXSquaredFactor  Nov 28, 2017

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