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# Factors and Numbers. Yes, this is kind of silly.

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(deleted)

Apr 24, 2020
edited by somehelpplease  May 8, 2020

### 11+0 Answers

#1
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I wrote a computer program, and got 7200.

Apr 24, 2020
#3
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That was wrong. Thanks for trying, though.

somehelpplease  Apr 24, 2020
#2
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xxxxxxxxxxxx

Apr 24, 2020
edited by Guest  Apr 24, 2020
#4
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Do you want each number to be divisible by 2, 5, 10 simultaneously or separately?

Guest Apr 24, 2020
#5
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"or," so seperately.

somehelpplease  Apr 24, 2020
#6
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Example:

How many integers less than or equal to 20 are divisible by 2? 5? or 10?

20/2 = 10

2, 4, 6, 8, 10, 12, 14, 16, 18, 20

20/5 = 4

5, 10, 15, 20

20/10 = 2

10, 20

10 + (4/2)because every 2 numbers there is a even number - 2 = 10

____________________________________________________________

Now apply the same to 10,000

Apr 24, 2020
edited by AnExtremelyLongName  Apr 24, 2020
#9
+109492
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For your example question, you have the right answer, but the wrong reason.

10+4-2 = 12

Because you have counted 10 and 20 twice.

Melody  Apr 25, 2020
#11
+626
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Thanks! Not gonna edit it because people can learn from my mistake.

AnExtremelyLongName  Apr 27, 2020
#7
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a=0;b=0;c=0;d=0;p=0; cycle:n=a*1000+b*100+c*10+d;if(n%2==0 or n%5==0 or n%10==0, goto loop, goto next); loop:printn,", ",;p=p+1; next:d++;if(d<10, goto cycle, 0);d=0;c++;if(c<10, goto cycle, 0);d=0;c=0;b++;if(b<10, goto cycle,0);b=0;c=0;d=0;a++;if(a<10, goto cycle,0);print"Total = ",p

OUTPUT = 6,000 such integers.

Apr 24, 2020
#8
+109492
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10000/2=5000

10000/5=2000

10000/10=1000

5000+2000-1000 = 6000

Definitely 6000

Apr 25, 2020
#10
+212
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Thanks for everyone's help! I really appreciate it. I got it. Have a nice day! :D

Apr 25, 2020