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A worker is supposed to dig a well 37m deep. He charges 1 euro cent for the first meter, but then the price is to be increased by 50% from meter to meter. The client agrees to this. What amount does he have to pay?

 Jun 26, 2021

Best Answer 

 #1
avatar+509 
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"He charges 1 euro cent for the first meter, but then the price is to be increased by 50% from meter to meter."

Let's take this into account as an GP such that

       GP = 1, 1.5, 2.25,... and so on

⇒ a = 1     and      r = 1.5 

 

Length of the well is 37 m i.e. the no. of terms in the GP is 37. 

Now, in order to calculate the total amount, we find the sum of 37 terms in the GP

         ∵ \({S}_{n}={a(r^n-1)\over r-1}\)

        ⇒ \({S}_{37} = {1((1.5)^{37}-1)\over 1.5-1} ≈ 6552491.2\)

 

Thus he has to pay 6,552,491.2 euro cents

 Jun 26, 2021
 #1
avatar+509 
+3
Best Answer

"He charges 1 euro cent for the first meter, but then the price is to be increased by 50% from meter to meter."

Let's take this into account as an GP such that

       GP = 1, 1.5, 2.25,... and so on

⇒ a = 1     and      r = 1.5 

 

Length of the well is 37 m i.e. the no. of terms in the GP is 37. 

Now, in order to calculate the total amount, we find the sum of 37 terms in the GP

         ∵ \({S}_{n}={a(r^n-1)\over r-1}\)

        ⇒ \({S}_{37} = {1((1.5)^{37}-1)\over 1.5-1} ≈ 6552491.2\)

 

Thus he has to pay 6,552,491.2 euro cents

amygdaleon305 Jun 26, 2021

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