Father’s age is 4 times that of his son. 5 years back, it was 7 times. His age now is
Ok. You can use whatever symbols you like for both son's age and father's age. Let me use x for son's age and y for father's age then.
father (y) is now 4 times as old as son (x) is now. y = 4x ...(1)
5 years ago father was y-5 years old, and son was x-5 years old. At that time father was 7 times as old as his son.
y - 5 = 7*(x - 5) ...(2)
Replace the y in (2) by using (1)
4x - 5 = 7*(x - 5)
4x - 5 = 7x - 35
4x - 5 + 35 = 7x
4x +30 = 7x
4x + 30 - 4x = 7x - 4x
30 = 3x
x = 10 ...(3)
Put (3) into (1)
y = 4*10
y = 40
Is this any clearer?
Let f = father's age and s = son's age
f = 4*s father is 4 times older than son
f - 5 = 7*(s - 5) 5 years ago father was f -5 and son was s-5 and father was 7 times older
Replace f in 2nd equation above with 4s from first equation,
4*s - 5 = 7*s - 7*5 so that:
30 = 3*s
s = 10
f = 4*10 = 40
Alan this question is still confusing me . Can you please put x in place of sons age and then try and solve this maybe that way I can understand this much easily!
Ok. You can use whatever symbols you like for both son's age and father's age. Let me use x for son's age and y for father's age then.
father (y) is now 4 times as old as son (x) is now. y = 4x ...(1)
5 years ago father was y-5 years old, and son was x-5 years old. At that time father was 7 times as old as his son.
y - 5 = 7*(x - 5) ...(2)
Replace the y in (2) by using (1)
4x - 5 = 7*(x - 5)
4x - 5 = 7x - 35
4x - 5 + 35 = 7x
4x +30 = 7x
4x + 30 - 4x = 7x - 4x
30 = 3x
x = 10 ...(3)
Put (3) into (1)
y = 4*10
y = 40
Is this any clearer?