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Find a base 7 three-digit number which has its digits reversed when expressed in base 9.

 Mar 9, 2019
 #1
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\(\text{let the number be }abc\\ 49a+7b+c = 81c+9b+a\\ 48a-2b=80c\\ c = \dfrac{24a-b}{40}\)

 

I'll let you figure out what the valid numbers are using the equation for c above.

Remember digits can only range from 0-6.

And of course digits have to be whole numbers.

 Mar 10, 2019

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