Find a degree 3 polynomial that has zeros - 3, 1 and 6 and in which the coefficient of x^2 is -12

Question

0

1748

1

Guest May 19, 2015

+128473

+5

Best Answer

P(x) = (x+3)(x - 1) (x - 6) = x^3 - 4x^2 - 15x + 18

So....to have a coefficient of -12 on the x^2 term, we need this

P(x) = (3) [ x^3 - 4x^2 - 15x + 18] = 3x^3 - 12x^2 - 45x + 54

CPhill May 19, 2015

CPhill · Answer 1 · 2015-05-19T10:24:58

P(x) = (x+3)(x - 1) (x - 6) = x^3 - 4x^2 - 15x + 18

So....to have a coefficient of -12 on the x^2 term, we need this

P(x) = (3) [ x^3 - 4x^2 - 15x + 18] = 3x^3 - 12x^2 - 45x + 54