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Find a degree 3 polynomial that has zeros - 3, 1 and 6 and in which the coefficient of x^2 is -12

Guest May 19, 2015

Best Answer 

 #1
avatar+92565 
+5

P(x) = (x+3)(x - 1) (x - 6)  = x^3 - 4x^2 - 15x + 18

 

So....to have a coefficient of -12 on the x^2 term, we need  this

 

P(x) = (3) [ x^3 - 4x^2 - 15x + 18]  =  3x^3 - 12x^2 - 45x + 54

 

CPhill  May 19, 2015
 #1
avatar+92565 
+5
Best Answer

P(x) = (x+3)(x - 1) (x - 6)  = x^3 - 4x^2 - 15x + 18

 

So....to have a coefficient of -12 on the x^2 term, we need  this

 

P(x) = (3) [ x^3 - 4x^2 - 15x + 18]  =  3x^3 - 12x^2 - 45x + 54

 

CPhill  May 19, 2015

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