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Find a monic quartic polynomial f(x) with rational coefficients whose roots include x=3-isqrt[4]2. <- it's supposed to look like the four is an exponent after the i. So, 3-i^4 sqrt2. Give your answer in expanded form.

 Jul 30, 2016

Best Answer 

 #1
avatar+23252 
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If  3 - i4sqrt(2)  =  3 - sqrt(2)  because i4 = 1.

 

If  3 - sqrt(2) is a root then (if the coefficients are rational), 3 + sqrt(2) is also a root.

 

If it's a quartic, you will have 2 more roots. They will be two rational roots [such as 2/3 and -7], or a pair of conjugate complex roots [such as 2 + 3i and 2 - 3i], or a pair of conjugate irrational roots [such as -5 + sqrt(19) and -5 - sqrt(19)].

 

(x - (3 - sqrt(2) ) · (x - (3 + sqrt(2)) · ( x - (something) ) · ( x - (something)  =  0

 Jul 31, 2016
 #1
avatar+23252 
0
Best Answer

If  3 - i4sqrt(2)  =  3 - sqrt(2)  because i4 = 1.

 

If  3 - sqrt(2) is a root then (if the coefficients are rational), 3 + sqrt(2) is also a root.

 

If it's a quartic, you will have 2 more roots. They will be two rational roots [such as 2/3 and -7], or a pair of conjugate complex roots [such as 2 + 3i and 2 - 3i], or a pair of conjugate irrational roots [such as -5 + sqrt(19) and -5 - sqrt(19)].

 

(x - (3 - sqrt(2) ) · (x - (3 + sqrt(2)) · ( x - (something) ) · ( x - (something)  =  0

geno3141 Jul 31, 2016

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