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Find the smallest positive real number a so that the polynomial x6+3ax5+(3a2+3)x4+(a3+6a)x3+(3a2+3)x2+3ax+1=0
has at least one real root.

 

Thank you for helping me! All help is appreciated!!!

 Aug 15, 2020
 #2
avatar+118703 
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y=x^6 + 3ax^5 + (3a^2 + 3) x^4 + (a^3 + 6a) x^3 + (3a^2 + 3) x^2 + 3ax + 1

 

 

Looks like about 1.77.

 

https://www.desmos.com/calculator/gvxtwzesob

 Aug 16, 2020

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