Find all solutions to:
ab + 2a + 2b = −16
ac + 2a + 2c = 26
bc + 2b + 2c = −14.
Find all solutions to:
ab + 2a + 2b = −16
ac + 2a + 2c = 26
bc + 2b + 2c = −14
Hello juananother!
\( ab + 2a + 2b = −16\\ a(b+2)+2b=-16\\ a= -\dfrac{16+2b}{b+2}\\ \ \\ ac + 2a + 2c = 26\\ a(c+2)+2c=26\\ a= \dfrac{26-2c}{c+2} \)
\( -\dfrac{16+2b}{b+2}=\dfrac{26-2{ \color{BrickRed} c}}{{ \color{BrickRed} c}+2} \)
\(bc + 2b + 2c = −14\\ \color{BrickRed} c=( -\dfrac{14+2b}{b+2}) \)
\(-\dfrac{16+2b}{b+2}= \dfrac{26-2{ \color{BrickRed} (-\dfrac{14+2b)}{b+2}}}{{ \color{BrickRed} (-\dfrac{14+2b}{b+2})}+2}\)
\(b= -\dfrac{8}{3}\)
\(c= -\dfrac{14+2\cdot (-\dfrac{8}{3})}{-\dfrac{8}{3}+2}\)
\(c=-13\)
\(a= \dfrac{26-2(-13)}{(-13)+2} \)
\(a=-\dfrac{52}{11}\)
!
There have been at least two other (with better methods than this one) answers to this question posted within the last week.
Look for them.
"with better methods than this one" Is there any better math than right? At school?
!
Some methods are certainly better than others.
(Both good and bad methods should lead to the correct answer.)
Have you looked at the earlier answers ?