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Find all values of x such that               \(  \frac{2x}{x + 2} = -\frac{6}{x + 4}.\)
If you find more than one value, then list your solutions, separated by commas.

 May 5, 2020
edited by mathlete2008  May 5, 2020
 #1
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2x/(x + 2) = -6/(x + 4)

==> 2x(x + 2) = -6(x + 2)

==> 2x^2 + 2x = -6x - 12

==> 2x^2 + 8x - 12 = 0

==> x = sqrt(10) - 2, -sqrt(10) - 2 (quadratic formula)

 May 5, 2020
 #2
avatar+87 
0

It said it was wrong.

 May 5, 2020
 #3
avatar+1498 
+2

What's "it"?

 

No offense, but I'm sure melody would agree, since i've seen her say it before.

 

"Please arrange your problem properly".

 

I know how to use latex, but it's rather unpleasant to read raw code, even if it's easy for you just to copy from a website and paste it onto here.

 

\(\frac{2x}{x + 2} = -\frac{6}{x + 4}.\)

 

see? That's much better.

 

I don't know where this problem came from but i'm pretty sure it's from AoPS or something.

 May 5, 2020
 #4
avatar+87 
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Yeah, sorry. 

 May 5, 2020
 #5
avatar+87 
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"It" being the answer "x = sqrt(10) - 2, -sqrt(10) - 2."

 May 5, 2020
edited by mathlete2008  May 5, 2020
 #6
avatar+87 
0

I fixed the question.smiley

 May 5, 2020
 #7
avatar+1498 
+3

Get rid of the fractions by rearrangement, and then, rearrange to isolate x.

 

Here

 

2x * (x+4) = 6 * (x+2)

 

See what you can do.

 

I refered to "it" as the first it

 

You said "it said it was wrong"

 

WHO said it was wrong?

 

Ask if you have any questions :)

 May 6, 2020
 #8
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0

Stop trying to cheat on your homework.

 May 9, 2020

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