+122 Find all values of x such that \( \frac{2x}{x + 2} = -\frac{6}{x + 4}.\)
If you find more than one value, then list your solutions, separated by commas.
2x/(x + 2) = -6/(x + 4)
==> 2x(x + 2) = -6(x + 2)
==> 2x^2 + 2x = -6x - 12
==> 2x^2 + 8x - 12 = 0
==> x = sqrt(10) - 2, -sqrt(10) - 2 (quadratic formula)
+1009 What's "it"?
No offense, but I'm sure melody would agree, since i've seen her say it before.
"Please arrange your problem properly".
I know how to use latex, but it's rather unpleasant to read raw code, even if it's easy for you just to copy from a website and paste it onto here.
\(\frac{2x}{x + 2} = -\frac{6}{x + 4}.\)
see? That's much better.
I don't know where this problem came from but i'm pretty sure it's from AoPS or something.
+1009 Get rid of the fractions by rearrangement, and then, rearrange to isolate x.
Here
2x * (x+4) = 6 * (x+2)
See what you can do.
I refered to "it" as the first it
You said "it said it was wrong"
WHO said it was wrong?
Ask if you have any questions :)
