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Find an equation of a circle with center (−3,−7) whose graph is tangent to the x-axis

 

 

 Is (x+3)^2 + (y+7)^2=9 the answer?

 Sep 13, 2019

Best Answer 

 #1
avatar+371 
+3

I'm pretty sure that the equation would be 

(x+3)^2+(y+7)^2=49

 

i believe that the radius would be 7, meaning that the right side of the equation would equal 49.

 Sep 13, 2019
 #1
avatar+371 
+3
Best Answer

I'm pretty sure that the equation would be 

(x+3)^2+(y+7)^2=49

 

i believe that the radius would be 7, meaning that the right side of the equation would equal 49.

hellospeedmind Sep 13, 2019
 #2
avatar+136 
+1

Oh! so you got 49 by multiplying 7^2. That's where everything went downhill for me.

Thank you so much for the answer! 

Roxettna  Sep 13, 2019

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