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Find an equation of the line that satisfies the given conditions.

y-intercept 6; parallel to the line 2x+3y+7=0

 Jun 10, 2014

Best Answer 

 #1
avatar+3454 
+5

Well, if this line is parallel to the line 2x+3y+7=0, that means it is the same as that line, but with a different y intercept

2x+3y+7=0

/3   /3  /3                    ---Divide everything by 3

2/3x + y + 7/3 = 0

-2/3x          -7/3               ---Subtract from both sides

y = -2/3x - 7/3

This is the same line in the slope-intercept form.

y = -2/3x + 6

I just changed the y intercept to 6, which is what we need. This is the first way we could write our answer. Or we could turn it back into the standard form of a line.

y = -2/3x + 6

      +2/3x

2/3x + y = 6

or

2x + 3y = 18

 

Hope this helps.

 Jun 11, 2014
 #1
avatar+3454 
+5
Best Answer

Well, if this line is parallel to the line 2x+3y+7=0, that means it is the same as that line, but with a different y intercept

2x+3y+7=0

/3   /3  /3                    ---Divide everything by 3

2/3x + y + 7/3 = 0

-2/3x          -7/3               ---Subtract from both sides

y = -2/3x - 7/3

This is the same line in the slope-intercept form.

y = -2/3x + 6

I just changed the y intercept to 6, which is what we need. This is the first way we could write our answer. Or we could turn it back into the standard form of a line.

y = -2/3x + 6

      +2/3x

2/3x + y = 6

or

2x + 3y = 18

 

Hope this helps.

NinjaDevo Jun 11, 2014

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