c= sqrt A^2 - B^2 C = 8, A = 17 find B i have been trying with this problem a while now and i feel very dumb at the moment can anyone help
+78
\(C=\sqrt{{A}^{2}-{B}^{2}}\)
where we know that; \(C=8\) and; \(A=17\)
just put those numbers in for now;
\(8=\sqrt{{17}^{2}-{B}^{2}}\)
we need \({A}^{2}\)--\({B}^{2}\)to equal \({8}^{2}\) therefore;
\({17}^{2}-{B}^{2}=64\)
Minus 64 from both sides;
\({17}^{2}-{B}^{2}-64=0\)
Then add \({B}^{2}\) to both sides;
\({17}^{2}-64={B}^{2}\)
\({17}^{2}-64\) is equal to \(225\)
therefore \({B}^{2}=225\)
and \(B=15\)
+78
\(C=\sqrt{{A}^{2}-{B}^{2}}\)
where we know that; \(C=8\) and; \(A=17\)
just put those numbers in for now;
\(8=\sqrt{{17}^{2}-{B}^{2}}\)
we need \({A}^{2}\)--\({B}^{2}\)to equal \({8}^{2}\) therefore;
\({17}^{2}-{B}^{2}=64\)
Minus 64 from both sides;
\({17}^{2}-{B}^{2}-64=0\)
Then add \({B}^{2}\) to both sides;
\({17}^{2}-64={B}^{2}\)
\({17}^{2}-64\) is equal to \(225\)
therefore \({B}^{2}=225\)
and \(B=15\)
