Thanks Alan,
I will do some of what Alan did only a little slower
−y2+x+20y−94=0$Multbothsidesby−1$y2−x−20y+94=0y2−20y−x=−94(y2−20y+(−202)2)−x=−94+(−202)2)(y2−20y+100)−x=−94+100(y−10)2−x=6(y−10)2=x+6
this is sideways parabola that opens out in the positive direction.
I know it is a parabola because one of the varibables is squared but not the other. And both are on the top and they are not multiplied together or anything strange like that.
I know it is sideways because it is the y that is squared, not the x.
I know it opens out in the positive direction because the number in front of the y^2 is an invisable 1 and it is Positive
I can see that the vertex is (-6,10)
I can see other things too but that might be enough for now. Alan's graph will hopefully backup everything that I have said. :)
PS. There was a small error that i have fixed. Thanks Alan
This can be re-written as (y - 10)2 = x + 6, so y = 10 ± √(x + 6)
This is a parabola.
.
Thanks Alan,
I will do some of what Alan did only a little slower
−y2+x+20y−94=0$Multbothsidesby−1$y2−x−20y+94=0y2−20y−x=−94(y2−20y+(−202)2)−x=−94+(−202)2)(y2−20y+100)−x=−94+100(y−10)2−x=6(y−10)2=x+6
this is sideways parabola that opens out in the positive direction.
I know it is a parabola because one of the varibables is squared but not the other. And both are on the top and they are not multiplied together or anything strange like that.
I know it is sideways because it is the y that is squared, not the x.
I know it opens out in the positive direction because the number in front of the y^2 is an invisable 1 and it is Positive
I can see that the vertex is (-6,10)
I can see other things too but that might be enough for now. Alan's graph will hopefully backup everything that I have said. :)
PS. There was a small error that i have fixed. Thanks Alan