#2**+10 **

Thanks Alan,

I will do some of what Alan did only a little slower

$$\\-y^2 + x + 20y - 94 = 0\\\\

$Mult both sides by -1 $\\\\

y^2 - x - 20y + 94 = 0\\\\

y^2 - 20y- x =\;-94\\\\

(y^2 - 20y+(\frac{-20}{2})^2)- x =\;-94+(\frac{-20}{2})^2)\\\\

(y^2 - 20y+100)- x =\;-94+100\\\\

(y-10)^2- x =\;6\\\\

(y-10)^2 =\;x+6\\\\$$

this is sideways parabola that opens out in the positive direction.

I know it is a parabola because one of the varibables is squared but not the other. And both are on the top and they are not multiplied together or anything strange like that.

I know it is sideways because it is the y that is squared, not the x.

I know it opens out in the positive direction because the number in front of the y^2 is an invisable 1 and it is **Positive**

I can see that the vertex is (-6,10)

I can see other things too but that might be enough for now. Alan's graph will hopefully backup everything that I have said. :)

PS. There was a small error that i have fixed. Thanks Alan

Melody Mar 27, 2015

#1**+10 **

This can be re-written as (y - 10)^{2} = x + 6, so y = 10 ± √(x + 6)

This is a parabola.

.

Alan Mar 27, 2015

#2**+10 **

Best Answer

Thanks Alan,

I will do some of what Alan did only a little slower

$$\\-y^2 + x + 20y - 94 = 0\\\\

$Mult both sides by -1 $\\\\

y^2 - x - 20y + 94 = 0\\\\

y^2 - 20y- x =\;-94\\\\

(y^2 - 20y+(\frac{-20}{2})^2)- x =\;-94+(\frac{-20}{2})^2)\\\\

(y^2 - 20y+100)- x =\;-94+100\\\\

(y-10)^2- x =\;6\\\\

(y-10)^2 =\;x+6\\\\$$

this is sideways parabola that opens out in the positive direction.

I know it is a parabola because one of the varibables is squared but not the other. And both are on the top and they are not multiplied together or anything strange like that.

I know it is sideways because it is the y that is squared, not the x.

I know it opens out in the positive direction because the number in front of the y^2 is an invisable 1 and it is **Positive**

I can see that the vertex is (-6,10)

I can see other things too but that might be enough for now. Alan's graph will hopefully backup everything that I have said. :)

PS. There was a small error that i have fixed. Thanks Alan

Melody Mar 27, 2015