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-y^2 + x + 20y - 94 = 0

 Mar 27, 2015

Best Answer 

 #2
avatar+118696 
+10

Thanks Alan,

 

I will do some of what Alan did only a little slower

 

y2+x+20y94=0$Multbothsidesby1$y2x20y+94=0y220yx=94(y220y+(202)2)x=94+(202)2)(y220y+100)x=94+100(y10)2x=6(y10)2=x+6

 

this is sideways parabola that opens out in the positive direction.

I know it is a parabola because one of the varibables is squared but not the other.  And both are on the top and they are not multiplied together or anything strange like that.

I know it is sideways because it is the y that is squared, not the x.

I know it opens out in the positive direction because the number in front of the y^2 is an invisable 1 and it is Positive

I can see that the vertex is (-6,10)

I can see other things too but that might be enough for now.  Alan's graph will hopefully backup everything that I have said. :)

 

PS.  There was a small error      that i have fixed.  Thanks Alan

 Mar 27, 2015
 #1
avatar+33654 
+10

This can be re-written as (y - 10)2 = x + 6,  so y = 10 ± √(x + 6)

 

 Parabola

 

This is a parabola.

.

 Mar 27, 2015
 #2
avatar+118696 
+10
Best Answer

Thanks Alan,

 

I will do some of what Alan did only a little slower

 

y2+x+20y94=0$Multbothsidesby1$y2x20y+94=0y220yx=94(y220y+(202)2)x=94+(202)2)(y220y+100)x=94+100(y10)2x=6(y10)2=x+6

 

this is sideways parabola that opens out in the positive direction.

I know it is a parabola because one of the varibables is squared but not the other.  And both are on the top and they are not multiplied together or anything strange like that.

I know it is sideways because it is the y that is squared, not the x.

I know it opens out in the positive direction because the number in front of the y^2 is an invisable 1 and it is Positive

I can see that the vertex is (-6,10)

I can see other things too but that might be enough for now.  Alan's graph will hopefully backup everything that I have said. :)

 

PS.  There was a small error      that i have fixed.  Thanks Alan

Melody Mar 27, 2015

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