+386 The answer provided by my book is:
( sqrt(2) -9) x - 2y -3(sqrt(2) ) +45 = 0
Here is what I did with those two coords so far:
y=mx+b
9=3m+b
Solve for m:
m=(9-b)/3
Replace in formula with coord ( 5, sqrt(2) ):
sqrt(2) = 5m + b
sqrt(2) = 5 ( (9-b)/3 ) + b
Solve for b:
b = 45 - 3( sqrt (2) )
So now I have both m and b values
Wouldn't the equation of the straight line be :
y = ( (9-b) / 3 ) x + ( 45 -3 ( sqrt (2) ) )
??? I'm confused as to what the book provides as the answer...
+37155 y= mx + b = equation for a line
m= slope = (y2-y1)/(x2-x1) = (sqrt2-9)/(5-3) = (sqrt2-9)/2
y = (sqrt2-9)/2 x + b
9 = (sqrt2-9)/2 (3) + b
9 = (3 sqrt2-27)/2 + b
b = 9 - (3sqrt2-27)/2
= 18/2 - (3sqrt2)/2 + 27/2
b= 45/2 - (3sqrt2)/2
so equation becomes y = (sqrt2-9)/2 x + 45/2 - (3sqrt2)/2 Multiply everything by '2'
2y = (sqrt2-9)x + 45 - (3sqrt2) subtract 2y from both sides and you will see your answer !
