+152 For the function
x-3/x^2 - 5x + 6
Find the points and draw the graph.
also, what happens to the graph at x=2? and at x=3?
If you factor $${{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{6}}$$
you should get (x-3)(x-2) in the denominator.
Since division by zero is not allowed, when x has a value of 2 or 3, the graph has what are called vertical asymptotes.
Hope I spelled that right. You should note also that now cancellation of (x-3) is possible from the numerator and denominator. The graph should look the same but you must still consider the points where the denominator equals zero as not allowed.
