+386
The sum of 2 numbers is 4 (sqrt 3) and their product is 3.
Determine quadratic equation which finds these two numbers
Then solve this equation and show that it's roots are in fact the two said numbers.
+37084 oOOPS......here is how
x+y = 4 (sqrt3)
x*y = 3 so y = 3/x (sub this into the first equation)
x + 3/x = 4 sqrt3 Multiply through by 'x'
x^2 + 3 = 4 sqrt 3 x re-arrange
x^2 - 4 sqrt3 x + 3 = 0 Now use the quadratic formula to find 2 (sqrt 3)-3 and 2 (sqrt 3) + 3
Quadratic Formula:
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
+37084 oOOPS......here is how
x+y = 4 (sqrt3)
x*y = 3 so y = 3/x (sub this into the first equation)
x + 3/x = 4 sqrt3 Multiply through by 'x'
x^2 + 3 = 4 sqrt 3 x re-arrange
x^2 - 4 sqrt3 x + 3 = 0 Now use the quadratic formula to find 2 (sqrt 3)-3 and 2 (sqrt 3) + 3
Quadratic Formula:
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
