Find the area A of the triangle whose sides have the given lengths. (Round your answer to the nearest integer.) a = 11, b = 115, c = 1

This can be solved with Heron's formula, which states that the area of a triangle with side lengths \(a, b\) and \(c\) and semiperimeter \(s\) has area\(\sqrt{s(s-a)(s-b)(s-c)}\). Applying this we have the area of the triangle is \(\sqrt{121\cdot 231\cdot 127\cdot 126} \approx 15926\). I hope this was helpful! :D