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# Find the area A of the triangle whose sides have the given lengths. (Round your answer to the nearest integer.) a = 11, b = 115, c = 1

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Find the area A of the triangle whose sides have the given lengths. (Round your answer to the nearest integer.)

a = 11,    b = 115,    c = 116

A = _____________

Dec 6, 2020

This can be solved with Heron's formula, which states that the area of a triangle with side lengths $$a, b$$ and $$c$$ and semiperimeter $$s$$ has area$$\sqrt{s(s-a)(s-b)(s-c)}$$. Applying this we have the area of the triangle is $$\sqrt{121\cdot 231\cdot 127\cdot 126} \approx 15926$$. I hope this was helpful! :D