+0  
 
0
76
8
avatar+2297 

So this one is just a triangle but I would make it into 3 triangles right?

 Dec 4, 2018
 #1
avatar+15350 
+2

Just leave it as ONE triangle....    area = 1/2 base x height   (easy)

Perimeter = L1 + L2 + L3    ONE leg is easy = 4    the other two are the same and you will have to calculate them using didstance between two points method.....

 Dec 4, 2018
 #2
avatar+2297 
0

I'm not sure what that method is..?

RainbowPanda  Dec 4, 2018
 #6
avatar+3613 
+1

\(p_1=(x_1,y_1)\\p_2=(x_2,y_2)\\ d(p_1,p_2) = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)

Rom  Dec 4, 2018
 #4
avatar+2297 
0

Okay I got 9.8 for the perimeter, am I right? 

For the Area, would it be 1/2*4*9.8?

 Dec 4, 2018
 #5
avatar+15350 
+2

The perimeter is not the HEIGHT !   frown      Height for this triangle is   3

 

Perimeter = 4 (the base) + TWO times sqrt ((4-2)^2 + (1-4)^2) =  4   +   2 * sqrt 13= 11.21 units

ElectricPavlov  Dec 4, 2018
 #7
avatar+2297 
0

Im so confused!! how did u get that for the perimeter?

RainbowPanda  Dec 4, 2018
 #8
avatar+15350 
+2

The BASE is 4   obviously ....right?

 

Distance between two points ( I KNOW you have seen this in recent days)

 

d^2 = (x1-x2)^2 + (y1-y2)^2     (this is just a Pythag Theorem re-written)

 

So using points    4,1    and  2,4           d^2 = (4-2)^2 + (1-4)^2   = 13     right?  

      so d = sqrt 13    the length of ONE leg....there are TWO of these legs 

               so  2 sqrt 13    PLUS the base (4) = perimeter = 11.21 units           

 

  Cool now?   You can do this.......cheeky

ElectricPavlov  Dec 4, 2018

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