So this one is just a triangle but I would make it into 3 triangles right?
Just leave it as ONE triangle.... area = 1/2 base x height (easy)
Perimeter = L1 + L2 + L3 ONE leg is easy = 4 the other two are the same and you will have to calculate them using didstance between two points method.....
Okay I got 9.8 for the perimeter, am I right?
For the Area, would it be 1/2*4*9.8?
The perimeter is not the HEIGHT ! Height for this triangle is 3
Perimeter = 4 (the base) + TWO times sqrt ((4-2)^2 + (1-4)^2) = 4 + 2 * sqrt 13= 11.21 units
The BASE is 4 obviously ....right?
Distance between two points ( I KNOW you have seen this in recent days)
d^2 = (x1-x2)^2 + (y1-y2)^2 (this is just a Pythag Theorem re-written)
So using points 4,1 and 2,4 d^2 = (4-2)^2 + (1-4)^2 = 13 right?
so d = sqrt 13 the length of ONE leg....there are TWO of these legs
so 2 sqrt 13 PLUS the base (4) = perimeter = 11.21 units
Cool now? You can do this.......