+0

​ Find the area and perimeter.

0
160
8
+2448

So this one is just a triangle but I would make it into 3 triangles right?

Dec 4, 2018

#1
+18293
+2

Just leave it as ONE triangle....    area = 1/2 base x height   (easy)

Perimeter = L1 + L2 + L3    ONE leg is easy = 4    the other two are the same and you will have to calculate them using didstance between two points method.....

Dec 4, 2018
#2
+2448
0

I'm not sure what that method is..?

RainbowPanda  Dec 4, 2018
#6
+5046
+1

$$p_1=(x_1,y_1)\\p_2=(x_2,y_2)\\ d(p_1,p_2) = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$$

Rom  Dec 4, 2018
#4
+2448
0

Okay I got 9.8 for the perimeter, am I right?

For the Area, would it be 1/2*4*9.8?

Dec 4, 2018
#5
+18293
+2

The perimeter is not the HEIGHT !         Height for this triangle is   3

Perimeter = 4 (the base) + TWO times sqrt ((4-2)^2 + (1-4)^2) =  4   +   2 * sqrt 13= 11.21 units

ElectricPavlov  Dec 4, 2018
#7
+2448
0

Im so confused!! how did u get that for the perimeter?

RainbowPanda  Dec 4, 2018
#8
+18293
+2

The BASE is 4   obviously ....right?

Distance between two points ( I KNOW you have seen this in recent days)

d^2 = (x1-x2)^2 + (y1-y2)^2     (this is just a Pythag Theorem re-written)

So using points    4,1    and  2,4           d^2 = (4-2)^2 + (1-4)^2   = 13     right?

so d = sqrt 13    the length of ONE leg....there are TWO of these legs

so  2 sqrt 13    PLUS the base (4) = perimeter = 11.21 units

Cool now?   You can do this.......

ElectricPavlov  Dec 4, 2018