Find the area of a parallelogram with sides of length 6 and 8, and with an interior angle with measure 45 degrees

How did you get the height asinus ?    

How did you get the height asinus ?   Thank's Melody!

parallelogram $ABCD$

 $\overline{AB}=a\\ \overline{BC}=s\\ triangle\ BAD=45°$

$perpendicular\ from\ D\ to\ a\ to\ point\ E\ is\ h.$

$AED\ is\ an\ isosceles\ right\ triangle.$  $(\overline {DE}=h)=\overline{AE}$

Set of Pythagoras:

$\overline {AD}\ ^2=\overline{DE}\ ^2+\overline{AE}\ ^2$

$s ^2=2h^2$

$h^2=\frac{s^2}{2}$

$\large h=\frac{s}{\sqrt{2}}$

  !

Thanks asinus :)