the shaded area is essentially the area of the trapezoid minus the area of that semi-circle.
the area of the trapezoid is
\(\frac{50+80}{2} \cdot (20 \cdot 2)\)
= \(\frac{130}{2} \cdot 40\)
= \(65 \cdot 40\)
= \(2600\)
the area of the semi-circle is
\(\frac{20^2 \cdot \pi}{2}\)
= \(\frac{400 \cdot \pi}{2}\)
= \(200 \pi\)
so, the area of the shaded region is \(2600 - 200\pi\).
hope this helped! please let me know if you have any questions