web2.0calc
 
+0  
 

 Find the area of the shape. Having very hard time with this help please! ​

0
805
7
avatar

Find the area of the shape. Having very hard time with this help please! 

 Apr 4, 2017

7+0 Answers

 #1
avatar+33661 
+1

A regular hexagon is comprised of six equilateral triangles.  The "base" of each triangle is just 10 cm (in this case) and the "height" is sqrt(102 - 52).

 

Can you take it from here?

 Apr 4, 2017
 #2
avatar
0

I understood the first part but Im confused at "is sqrt(10^2 - 5^2)". Is that the formula to solve?

Guest Apr 4, 2017
edited by Guest  Apr 4, 2017
 #3
avatar+33661 
+1

sqrt(102 - 52) → sqrt(100 - 25) → sqrt(75) → 5*sqrt(3)

 

This is the height of the black(?) line going from the centre to the side in your picture.

Alan  Apr 4, 2017
 #4
avatar+33661 
+1

The area of a triangle, of course, is given by half base times height.

Alan  Apr 4, 2017
 #5
avatar
0

So the two red lines and the black line make a triagnle that I solve the area for??? Sorry Im very confused now.

Guest Apr 4, 2017
 #6
avatar+33661 
+1

The two red lines and the purple(?) line between them form an equilateral triangle. Find the area of this and multiply by six to get the area of the hexagon.

Alan  Apr 4, 2017
edited by Alan  Apr 4, 2017
 #7
avatar
+1

Okay I understand thanks bro

Guest Apr 4, 2017

2 Online Users

avatar

Top Users

avatar+37146 ElectricPavlov
avatar+33661 Alan moderator
avatar+14995 asinus moderator
avatar+9673 MaxWong
avatar+2489 GingerAle
avatar+1908 NotThatSmart
avatar+1839 ABJeIIy
avatar+1768 bader
avatar+1537 parmen
avatar+1439 kittykat
avatar+1427 blackpanther

Sticky Topics