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# Find the area of the shape. Having very hard time with this help please! ​

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Find the area of the shape. Having very hard time with this help please!

Guest Apr 4, 2017
#1
+27128
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A regular hexagon is comprised of six equilateral triangles.  The "base" of each triangle is just 10 cm (in this case) and the "height" is sqrt(102 - 52).

Can you take it from here?

Alan  Apr 4, 2017
#2
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I understood the first part but Im confused at "is sqrt(10^2 - 5^2)". Is that the formula to solve?

Guest Apr 4, 2017
edited by Guest  Apr 4, 2017
#3
+27128
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sqrt(102 - 52) → sqrt(100 - 25) → sqrt(75) → 5*sqrt(3)

This is the height of the black(?) line going from the centre to the side in your picture.

Alan  Apr 4, 2017
#4
+27128
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The area of a triangle, of course, is given by half base times height.

Alan  Apr 4, 2017
#5
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So the two red lines and the black line make a triagnle that I solve the area for??? Sorry Im very confused now.

Guest Apr 4, 2017
#6
+27128
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The two red lines and the purple(?) line between them form an equilateral triangle. Find the area of this and multiply by six to get the area of the hexagon.

Alan  Apr 4, 2017
edited by Alan  Apr 4, 2017
#7
+1

Okay I understand thanks bro

Guest Apr 4, 2017

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