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i think that i should use like law of sines of cosines but I'm not sure, could I get some help, really don't know where to start...

 Jan 13, 2024
 #1
avatar+128408 
+1

Nah

 

If we know  an  included angle between two known sides,  the area = 

 

(1/2) ( product of the sides)* sine (of included angle)

 

So

 

(1/2) (6 * 6)  sin 45°

 

Can you take it  from  here  ???

 

cool cool cool

 Jan 13, 2024
 #2
avatar+180 
+1

yes, thank you!

 Jan 13, 2024

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