i think that i should use like law of sines of cosines but I'm not sure, could I get some help, really don't know where to start...
Nah
If we know an included angle between two known sides, the area =
(1/2) ( product of the sides)* sine (of included angle)
So
(1/2) (6 * 6) sin 45°
Can you take it from here ???
yes, thank you!
+180 
use like law of sines of cosines but I'm not sure, could I get some help, really don't know where to start...
